44 lines
1.2 KiB
C++
44 lines
1.2 KiB
C++
|
|
#include <bits/stdc++.h>
|
|||
|
|
using namespace std;
|
|||
|
|
const int N = 100010;
|
|||
|
|
|
|||
|
|
struct Node {
|
|||
|
|
int s; // 距离
|
|||
|
|
int b; // 疲劳值
|
|||
|
|
bool operator<(const Node &W) const {
|
|||
|
|
return b > W.b; // 按疲劳值从大到小排序
|
|||
|
|
}
|
|||
|
|
} a[N];
|
|||
|
|
|
|||
|
|
int main() {
|
|||
|
|
int n;
|
|||
|
|
cin >> n;
|
|||
|
|
for (int i = 1; i <= n; i++) cin >> a[i].s;
|
|||
|
|
for (int i = 1; i <= n; i++) cin >> a[i].b;
|
|||
|
|
|
|||
|
|
sort(a + 1, a + 1 + n);
|
|||
|
|
|
|||
|
|
for (int x = 1; x <= n; x++) {
|
|||
|
|
int max_dist = 0;
|
|||
|
|
int total_fatigue = 0;
|
|||
|
|
int max_alternative = 0;
|
|||
|
|
|
|||
|
|
// 计算前x个住户的总疲劳值和最大距离
|
|||
|
|
for (int i = 1; i <= x; i++) {
|
|||
|
|
total_fatigue += a[i].b;
|
|||
|
|
if (2 * a[i].s > max_dist) {
|
|||
|
|
max_dist = 2 * a[i].s;
|
|||
|
|
}
|
|||
|
|
// 计算替代方案:前x-1个疲劳值 + 第i个的距离*2+疲劳值
|
|||
|
|
int alternative = total_fatigue - a[i].b + 2 * a[i].s + a[i].b;
|
|||
|
|
if (alternative > max_alternative) {
|
|||
|
|
max_alternative = alternative;
|
|||
|
|
}
|
|||
|
|
}
|
|||
|
|
|
|||
|
|
int max_fatigue = max(total_fatigue + max_dist, max_alternative);
|
|||
|
|
cout << max_fatigue << endl;
|
|||
|
|
}
|
|||
|
|
|
|||
|
|
return 0;
|
|||
|
|
}
|