78 lines
1.3 KiB
C++
78 lines
1.3 KiB
C++
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#include <bits/stdc++.h>
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using namespace std;
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const int N = 110;
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//ע<>⣺n,mһ<6D><D2BB>Ҫ<EFBFBD><D2AA><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ȫ<EFBFBD>ֱ<EFBFBD><D6B1><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ϊcheck() <20><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ҫ<EFBFBD><D2AA>ȡ<EFBFBD><C8A1><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ݣ<EFBFBD><DDA3><EFBFBD><EFBFBD><EFBFBD>
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int n, m;
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int a[N][N];
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/*
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<EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
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3
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1 4
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0110
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5 5
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00000
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01100
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01100
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00001
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01100
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5 5
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00000
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01100
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01110
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00001
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01100
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*/
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bool check() {
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//0<><30><EFBFBD><EFBFBD> 1<><31><EFBFBD><EFBFBD>
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if (n < 4 || m < 4 ) //<2F><><EFBFBD><EFBFBD>4<EFBFBD><34>4<EFBFBD>У<EFBFBD>ֱ<EFBFBD><D6B1><EFBFBD>ж<EFBFBD><D0B6><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ԣ<EFBFBD><D4A3>ⲽ<EFBFBD><E2B2BD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>©
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return false;
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int s1 = 0, s4 = 0;
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for (int i = 1; i <= 4; i++) {
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s1 += a[1][i];//<2F><>һ<EFBFBD>еĺ<D0B5>
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s4 += a[4][i];//<2F><><EFBFBD><EFBFBD><EFBFBD>еĺ<D0B5>
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}
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if (s1 || s4)//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>һ<EFBFBD>л<EFBFBD><D0BB><EFBFBD><EFBFBD><EFBFBD><EFBFBD>в<EFBFBD>ȫ<EFBFBD>ǰ<EFBFBD>ɫ
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return false;
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//<2F><>2<EFBFBD>У<EFBFBD><D0A3><EFBFBD>3<EFBFBD><33>
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if (a[2][1] || a[2][4])//(2,1),(2,4)<29><><EFBFBD><EFBFBD><EFBFBD>Ǻ<EFBFBD>ɫ<EFBFBD><C9AB>
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//<2F>ж<EFBFBD><D0B6><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>,ע<>⣺<EFBFBD><E2A3BA><EFBFBD><EFBFBD>Ҫд<D2AA><D0B4><EFBFBD><EFBFBD><EFBFBD>Եģ<D4B5><C4A3><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ľ<EFBFBD><C4BE>ǿ<EFBFBD><C7BF>Ե<EFBFBD>
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return false;
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if (!a[2][2] || !a[2][3])
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return false;
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if (a[3][1] || a[3][4])
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return false;
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if (!a[3][2] || !a[3][3])
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return false;
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return true;
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}
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int main() {
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int T;
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cin >> T;
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while (T--) {
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cin >> n >> m;
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for (int i = 1; i <= n; i++) {
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string s;//<2F><>Ϊ01<30>м<EFBFBD><D0BC>ո<DEBF><D5B8><EFBFBD>ʹ<EFBFBD><CAB9>string<6E><67><EFBFBD>ж<EFBFBD>ȡ<EFBFBD><C8A1><EFBFBD>ٷֲ<D9B7><D6B2><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>a[N][N]<5D><>
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cin >> s;
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for (int j = 1; j <= m; j++)
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a[i][j] = s[j - 1] - '0';//Ҫע<D2AA><D7A2>string<6E>±<EFBFBD><C2B1>Ǵ<EFBFBD>0<EFBFBD><30>ʼ<EFBFBD>ģ<EFBFBD><C4A3><EFBFBD><EFBFBD><EFBFBD>j<EFBFBD><6A>Ҫ<EFBFBD><D2AA>1
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}
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if (check())
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cout << "Yes" << endl;
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else
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cout << "No" << endl;
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}
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return 0;
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}
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