20 lines
470 B
C++
20 lines
470 B
C++
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#include <bits/stdc++.h>
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using namespace std;
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int main() {
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int n = 1, ans = 0;
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for (int i = 1; i <= 2019; i++) n = n * 2019 % 100; //计算出n'
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// 1~11的n次方
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for (int i = 1; i <= 11; i++) {
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int x = 1;
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for (int j = 1; j <= n; j++) x = x * i % 101; //降幂后可以正常按要求计算
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//收集答案
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ans += x;
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}
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//最终也要模一下101
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printf("%d\n", ans % 101);
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return 0;
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}
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