63 lines
1.3 KiB
C++
63 lines
1.3 KiB
C++
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#include <bits/stdc++.h>
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/*
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测试用例：
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5 6
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1 0 1 0 0 0
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0 1 0 1 0 0
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1 0 0 0 1 0
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0 1 0 0 0 1
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1 0 1 0 0 0
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测试用例II：
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5 6
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1 0 1 0 0 0 2 0 4 0 0 0
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0 1 0 1 1 0 0 1 0 3 1 0
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1 0 0 0 1 0 3 0 0 0 2 0
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0 1 0 0 0 1 0 2 0 0 0 1
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1 0 1 0 0 0 1 0 1 0 0 0
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5 6
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1 0 1 0 0 0
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0 1 0 1 1 0
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1 0 0 0 1 0
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0 1 0 0 0 1
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1 0 1 0 0 0
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测试用例III：
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5 6
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1 0 1 0 0 0
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0 1 0 1 1 0
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1 0 0 0 1 0
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0 1 0 1 0 1
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1 0 1 0 1 0
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*/
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using namespace std;
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const int N = 110;
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int a[N][N];
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int res;
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int main() {
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int n, m;
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cin >> n >> m;
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for (int i = 1; i <= n; i++)
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for (int j = 1; j <= m; j++)
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cin >> a[i][j];
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//直接在原数组上递推
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for (int i = n; i >= 1; i--) //从倒数第二行开始
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for (int j = 1; j <= m; j++) //这个需要考虑一下边界问题
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if (a[i][j]) //只有当前位置大于0才有考虑的价值
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a[i][j] += a[i + 1][j + 1]; //递推式
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cout << "====================" << endl;
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//打印出这个新的递推数组看看是什么情况
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= m; j++)
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cout << a[i][j] << " ";
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cout << endl;
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}
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return 0;
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}
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