30 lines
1.1 KiB
C++
30 lines
1.1 KiB
C++
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#include <bits/stdc++.h>
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using namespace std;
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const int N = 1010, M = 10010;
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int T, n, m;
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int f[M];
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int w[N][N]; //第i天,第j支股票的价格
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int main() {
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//未来天数 T，纪念品数量 N，小伟现在拥有的金币数量 M
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cin >> T >> n >> m;
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for (int i = 1; i <= T; i++) //未来T天
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for (int j = 1; j <= n; j++) //每个纪念品
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cin >> w[i][j]; //价格
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for (int t = 1; t < T; t++) { //枚举每一天
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memset(f, 0, sizeof f); // dp数组
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for (int i = 1; i <= n; i++) //枚举前i种物品
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for (int j = w[t][i]; j <= m; j++) //枚举剩余体积
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f[j] = max(f[j], f[j - w[t][i]] + w[t + 1][i] - w[t][i]); //收益=w[t + 1][i] - w[t][i]
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//因为赚了钱，所以后面一天的初始金额变大，这是一个逐步累加的过程.也就是背包容量变大
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m += f[m];
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}
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printf("%d\n", m);
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return 0;
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}
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