53 lines
2.0 KiB
C++
53 lines
2.0 KiB
C++
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/*/*******************************************************************************
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** **
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** Jiedi(China nanjing)Ltd. **
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** 创建：丁宋涛 夏曹俊，此代码可用作为学习参考 **
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*******************************************************************************/
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/*****************************FILE INFOMATION***********************************
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**
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** Project : 算法设计与编程实践---基于leetcode的企业真题库
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** Contact : xiacaojun@qq.com
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** 博客 : http://blog.csdn.net/jiedichina
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** 视频课程 : 网易云课堂 http://study.163.com/u/xiacaojun
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腾讯课堂 https://jiedi.ke.qq.com/
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csdn学院 https://edu.csdn.net/course/detail/25037
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** 51cto学院 http://edu.51cto.com/lecturer/index/user_id-100013755.html
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** 老夏课堂 http://www.laoxiaketang.com
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**
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** 算法设计与编程实践---基于leetcode的企业真题库 课程群 ：296249312 加入群下载代码和交流
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** 微信公众号 : jiedi2007
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** 头条号 : 夏曹俊
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**
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*****************************************************************************
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//！！！！！！！！！ 算法设计与编程实践---基于leetcode的企业真题库 课程 QQ群：296249312 下载代码和交流*/
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/*
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* @lc app=leetcode.cn id=112 lang=cpp
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*
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* [112] 路径总和
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*/
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
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* };
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*/
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class Solution {
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public:
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bool hasPathSum(TreeNode* root, int sum) {
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if(root == NULL)
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return false;
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if(root->left == NULL && root->right == NULL){
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return root->val == sum;
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}
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return hasPathSum(root->left,sum-root->val)
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|| hasPathSum(root->right,sum-root->val);
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}
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};
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