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HuangHai
2025-08-30 18:35:01 +08:00
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![](http://dsideal.obs.cn-north-1.myhuaweicloud.com/HuangHai/BlogImages/2023/04/5265283b0c47a6aad5c85b0a0835994c.png)
- $\triangle ABF \cong \triangle AED$
- $\therefore \angle 2=\angle BAF$
- $\because \angle 3+\angle FAB=90^{\circ}$
- $\therefore \angle 2+\angle 3=90^{\circ}$
- 画出外接隐藏圆,以$O$为圆心
- 套路,满满的套路!找出一个三角形吧:$\triangle OGB$!,$BG>=OB-OG$!