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HuangHai
2025-08-30 18:35:01 +08:00
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![](http://dsideal.obs.cn-north-1.myhuaweicloud.com/HuangHai/BlogImages/2023/04/133d6ca046e08fc50ca41d76c22f6653.png)
- 直角三角形,斜边中线,等于斜边一半 $BG=\frac{1}{2}EF=2$
- $BG$长度固定,则$G$在以$B$为圆心,长度为$2$的圆上运动
- 四边形面积最小,可以看成上面的三角形$ACD$是固定值,只要$\triangle AGC$面积最小即可,从$G$向$AC$引垂线,则$S_{\triangle AGC}=\frac{1}{2}AC\times GM$
- $GM$什么时候最短呢?
- $GM>=BM-BG>=BH-BG$
所以求出$BH$即可,按面积相等求解吧