'commit'

C++课程/待整理知识/啊哈算法/dfs宝岛探险.cpp

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+/*<2A><>ɫ<EFBFBD><C9AB>:<3A><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ż<EFBFBD><C5BB><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>color<6F>IJ<EFBFBD><C4B2><EFBFBD>*/
+#include<stdio.h>
+
+int a[51][51];
+int book[51][51];
+int n, m, sum;
+void dfs(int x, int y, int color) {
+	int k, tx, ty;
+	//<2F><><EFBFBD><EFBFBD>һ<EFBFBD><D2BB><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+	int next[4][2] = { { 0, 1 },//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+		{ 1, 0 },//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+		{ 0, -1 },//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+		{ -1, 0 }
+	};//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+
+	a[x][y] = color;//<2F><>a[x][y]<5D><><EFBFBD><EFBFBD>Ⱦɫ
+
+	//ö<><C3B6><EFBFBD>ĸ<EFBFBD><C4B8><EFBFBD><EFBFBD><EFBFBD>
+	for (k = 0; k<4; k++) {
+		//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>һ<EFBFBD><D2BB><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>
+		tx = x + next[k][0];
+		ty = y + next[k][1];
+
+		//<2F>ж<EFBFBD><D0B6>Ƿ<EFBFBD>Խ<EFBFBD><D4BD>
+		if (tx<1 || tx>n || ty<1 || ty>m)
+			continue;
+
+		//<2F>ж<EFBFBD><D0B6>Ƿ<EFBFBD><C7B7><EFBFBD>½<EFBFBD><C2BD>
+		if (a[tx][ty]>0 && book[tx][ty] == 0) {
+			sum++;
+			book[tx][ty] = 1; //<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ѿ<EFBFBD><D1BE>߹<EFBFBD>
+			dfs(tx, ty, color);//<2F><>ʼ<EFBFBD><CABC><EFBFBD><EFBFBD><EFBFBD><EFBFBD>һ<EFBFBD><D2BB><EFBFBD><EFBFBD>
+		}
+	}
+	return;
+}
+
+int main() {
+	int i, j, startx, starty;
+	scanf("%d %d %d %d", &n, &m, &startx, &starty);
+
+	//<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ͼ
+	for (i = 1; i <= n; i++)
+		for (j = 1; j <= m; j++)
+			scanf("%d", &a[i][j]); //<2F><><EFBFBD><EFBFBD><EFBFBD><EFBFBD>ͼ
+
+	book[startx][starty] = 1;
+	sum = 1;
+	dfs(startx, starty, -1);//<2F><>-1<><31>ʾ<EFBFBD><CABE><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD><EFBFBD>Ⱦɫ
+
+	//<2F><><EFBFBD><EFBFBD><EFBFBD>Ѿ<EFBFBD>Ⱦɫ<C8BE><C9AB><EFBFBD>ĵ<EFBFBD>ͼ
+	for (i = 1; i <= n; i++) {
+		for (j = 1; j <= m; j++) {
+			printf("%3d", a[i][j]);//%3d<33>е<EFBFBD>3<EFBFBD><33>c<EFBFBD><63><EFBFBD><EFBFBD><EFBFBD>еij<D0B5><C4B3><EFBFBD>
+		}
+		printf("\n");
+	}
+	getchar();
+	getchar();
+	return 0;
+}