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35
TangDou/AcWing/BeiBao/FangAnShu/ZhiDuo_01_ErWei.cpp
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35
TangDou/AcWing/BeiBao/FangAnShu/ZhiDuo_01_ErWei.cpp
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#include <bits/stdc++.h>
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using namespace std;
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const int N = 110;
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int n, m;
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int f[N][N]; //第一维:前i个物品,第二维:体积j及以下
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int main() {
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//文件输入
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freopen("ZhiDuo_01.in", "r", stdin);
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scanf("%d %d", &n, &m);
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//初始化
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//在前0个物品中选,所有合法空间,都有一种结果,就是啥也不要,啥也不要也满足“不超过j”这个条件,方案数=1。
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for (int i = 0; i <= m; i++) f[0][i] = 1;
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for (int i = 1; i <= n; i++) {
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int v;
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scanf("%d", &v);
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/*写法1*/
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for (int j = 0; j <= m; j++) {
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if (j >= v)
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f[i][j] = f[i - 1][j] + f[i - 1][j - v];
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else
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f[i][j] = f[i - 1][j];
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}
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/*写法2*/
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// for (int j = 0; j <= m; j++) {
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// f[i][j] = f[i - 1][j]; //不被i件物品
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// if (j >= v) f[i][j] += f[i - 1][j - v]; //能装下就要加上可以转移过来状态的方案数
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// }
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}
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printf("%d\n", f[n][m]);
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return 0;
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}
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