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35
TangDou/CSP-J/AcWingTraining/T4/474.cpp
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35
TangDou/CSP-J/AcWingTraining/T4/474.cpp
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#include <bits/stdc++.h>
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using namespace std;
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#define int long long
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const int N = 100010;
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int n;
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int m, p1, p2, s1, s2;
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int c[N];
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signed main() {
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cin >> n; // 代表兵营的数量
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for (int i = 1; i <= n; i++) cin >> c[i]; // 起始时的工兵数量 ci
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cin >> m >> p1 >> s1 >> s2;
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// 以 m 号兵营作为分界
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// s1 位工兵突然出现在了 p1 号兵营
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// 需要选择一个兵营 p2,并将你手里的 s2 位工兵全部派往兵营 p2
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c[p1] += s1;
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int s = 0;
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for (int i = 1; i <= n; i++) s += c[i] * (m - i); // 双方气势差距
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int res = 1e18;
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for (int i = 1; i <= n; i++) { // 遍历每个兵营,看看放哪个兵营差距最小
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int t = (m - i) * s2 + s;
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if (abs(t) < res) {
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res = abs(t);
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p2 = i;
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}
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}
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printf("%lld\n", p2);
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return 0;
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}
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