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36
TangDou/LanQiaoBei/LanQiaoBei13GuoSai/3_3.cpp
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36
TangDou/LanQiaoBei/LanQiaoBei13GuoSai/3_3.cpp
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#include <iostream>
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#include <queue>
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#include <vector>
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using namespace std;
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int main() {
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int N; // 木桩的数量
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cin >> N;
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vector<int> nums(N); // 每个木桩上的数字
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for (int i = 0; i < N; i++) {
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cin >> nums[i];
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}
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vector<int> steps(N, -1); // 每个木桩的步数,初始值设为-1
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steps[0] = 0; // 第一个木桩的步数为0
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queue<int> q; // 存储已经遍历了的木桩
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q.push(0);
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while (!q.empty()) {
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int cur = q.front();
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q.pop();
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for (int i = cur + 1; i <= cur + nums[cur] && i < N; i++) {
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if (steps[i] == -1 || steps[i] > steps[cur] + 1) {
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steps[i] = steps[cur] + 1;
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q.push(i);
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}
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}
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}
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cout << steps[N - 1] << endl; // 输出最后一个木桩的步数
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return 0;
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}
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