'commit'

TangDou/LuoGuBook/第8章模拟与高精度/P4924_1.cpp

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+#include <bits/stdc++.h>
+
+using namespace std;
+
+// Rotate Image（二维数组逆时针旋转90度）
+const int N = 110;
+int n = 9, cnt;
+int res[N][N], f[N][N];
+
+//矩阵旋转，需要额外开创建一个临时的二维数组(防止出现交换赋值时，出现覆盖的问题)
+void rotate(int x, int y, int r) { // x:第几行 y:以(x,y)点为中心，四个方向，向左r,向右r，转~
+    for (int i = -r; i <= r; i++)
+        for (int j = -r; j <= r; j++) //
+            f[x - j][y + i] = res[x + i][y + j]; //副本修改
+
+    // 复制数组的正规写法
+    memcpy(res, f, sizeof f); //将副本复制回到正本上
+
+    //复制
+    // for (int i = 1; i <= n; i++)
+    //     for (int j = 1; j <= n; j++)
+    //         res[i][j] = f[i][j];
+}
+
+int main() {
+    //初始化填充数据
+    for (int i = 1; i <= n; i++)
+        for (int j = 1; j <= n; j++)
+            res[i][j] = f[i][j] = ++cnt;
+
+    //输出结果
+    for (int i = 1; i <= n; i++) {
+        for (int j = 1; j <= n; j++)
+            printf("%02d ", res[i][j]);
+        printf("\n");
+    }
+
+    printf("\n");
+
+    //测试一下旋转
+    rotate(6, 7, 1);
+
+    //输出结果
+    for (int i = 1; i <= n; i++) {
+        for (int j = 1; j <= n; j++)
+            printf("%02d ", res[i][j]);
+        printf("\n");
+    }
+    return 0;
+}