#include using namespace std; typedef long long ll; const int N = 40; ll c[N][N]; int main(){ for(int i = 0; i < N; i++){ for(int j = 1; j <= i; j++) if(!j)c[i][j] = 1; else c[i][j] = c[i-1][j] + c[i-1][j-1]; } int n; cin >> n; cout << c[n*2][n]/(n+1) << endl; return 0; }