#include<iostream>

using namespace std;

struct Date {
    int year;
    int month;
    int day;
};
int months_1[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};
int months_2[13] = {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};

bool LeapYear(int year) {
    return ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0);
}

//计算到元年元月元日的差
int getAbsDay(Date x) {
    int n = 0;
    //以往年有多少天
    for (int i = 1900; i < x.year; i++)
        n += (LeapYear(i)) ? 366 : 365;
    //月-->天数+
    for (int i = 1; i < x.month; i++)
        n += LeapYear(x.year) ? months_2[i] : months_1[i];
    //天数
    n += x.day;
    return n;
}

int main() {
    //计算两个日期对象的差
    Date a = {2021, 8, 26}; //周四
    Date b = {2021, 10, 11}; //?

    //计算到元年元月元日的差
    int n = getAbsDay(b) - getAbsDay(a);
    //输出
    printf("%d *%d", n, (n + 4) % 7);
    return 0;
}