#include <bits/stdc++.h>

using namespace std;
const int N = 1e5 + 10;
const int BASE = 10000; // 基数为10000

int a[N], al;

/*
3 3 6
100

答案:
6
9
648
 */

// 高精度乘以低精度
void mul(int a[], int &al, int b) {
  int t = 0;
  for (int i = 0; i < al; i++) {
    t += a[i] * b;
    a[i] = t % BASE;
    t /= BASE;
  }

  if (t)
    a[al++] = t;

  while (al > 1 && a[al - 1] == 0)
    al--;
}

// 计算压位数组所表示数字的各位之和
int digitSum() {
  int sum = 0;
  for (int i = 0; i < al; i++) {
    int x = a[i];
    while (x) {
      sum += x % 10;
      x /= 10;
    }
  }
  return sum;
}

int solve(int n) {
  // 初始化为1
  al = 1;
  a[0] = 1;

  // 计算阶乘
  for (int i = 2; i <= n; i++)
    mul(a, al, i);

  return digitSum();
}

int main() {
  int T;
  cin >> T;
  while (T--) {
    int n;
    cin >> n;
    cout << solve(n) << endl;
  }
  return 0;
}