#include /* 测试用例I: 3 7 答案:5 测试用例II: 4 15 答案:144 测试用例III: 1 22 答案:17711 */ using namespace std; int n, m; int f[110]; int main() { cin >> n >> m; f[2] = 1, f[3] = 2; for (int i = 4; i <= m - n + 1; i++) f[i] = f[i - 1] + f[i - 2]; printf("%d\n", f[m - n + 1]); return 0; }