## 背包问题-最大值-空间恰好$j$ ### 一、$01$背包 求价值最大值:初始化$f[0][0] = 0$, 其余是$-INF$ 例子:给你一堆物品,每个物品有一定的体积和对应的价值,每个物品只能选一个,求 总体积恰好是$j$的 最大价值 输入 ```c++ 4 5 1 2 2 4 3 4 4 5 ``` 输出 ```c++ 8 ``` #### 1、二维 ```c++ #include using namespace std; const int N = 110; const int INF = 0x3f3f3f3f; int n, m; int f[N][N]; int main() { //文件输入 freopen("QiaHao_01_Max.in", "r", stdin); scanf("%d %d", &n, &m); memset(f, -INF, sizeof f); f[0][0] = 0; for (int i = 1; i <= n; i++) { int v, w; scanf("%d %d", &v, &w); for (int j = 0; j <= m; j++) { f[i][j] = f[i - 1][j]; if (j >= v) f[i][j] = max(f[i][j], f[i - 1][j - v] + w); } } printf("%d\n", f[n][m]); return 0; } ``` #### 2、一维 ```c++ #include using namespace std; const int N = 110; const int INF = 0x3f3f3f3f; int n, m; int f[N]; int main() { //文件输入 freopen("QiaHao_01_Max.in", "r", stdin); scanf("%d %d", &n, &m); memset(f, -INF, sizeof f); f[0] = 0; for (int i = 1; i <= n; i++) { int v, w; scanf("%d %d", &v, &w); for (int j = m; j >= v; j--) f[j] = max(f[j], f[j - v] + w); } printf("%d\n", f[m]); return 0; } ``` ### 二、完全背包 求价值最大值:初始化$f[0][0] = 0$, 其余是$-INF$ 例子:给你一堆物品,每个物品有一定的体积和对应的价值,每个物品可以选无数多个,求 总体积恰好是$m$ 的 最大价值 输入 ```c++ 4 5 1 2 2 4 3 4 4 5 ``` 输出 ```c++ 10 ``` #### 1、二维 ```c++ #include using namespace std; const int N = 110; const int INF = 0x3f3f3f3f; int n, m; int f[N][N]; int main() { cin >> n >> m; memset(f, -INF, sizeof f); f[0][0] = 0; for (int i = 1; i <= n; i++) { int v, w; cin >> v >> w; for (int j = 0; j <= m; j++) { f[i][j] = f[i - 1][j]; if (j >= v) f[i][j] = max(f[i][j], f[i][j - v] + w); } } cout << f[n][m] << endl; return 0; } ``` #### 2、一维 ```c++ #include using namespace std; const int N = 110; const int INF = 0x3f3f3f3f; int n, m; int f[N]; int main() { //文件输入 freopen("QiaHao_WQ_Max.in", "r", stdin); scanf("%d %d", &n, &m); memset(f, -INF, sizeof f); f[0] = 0; for (int i = 1; i <= n; i++) { int v, w; scanf("%d %d", &v, &w); for (int j = v; j <= m; j++) f[j] = max(f[j], f[j - v] + w); } printf("%d\n", f[m]); return 0; } ```