14 lines
318 B
C++
14 lines
318 B
C++
#include <bits/stdc++.h>
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using namespace std;
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int main() {
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int x = 13;
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int ans = 0;
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for (int i = 30; i >= 0; i--) {
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int u = x >> i & 1; //取出x的当前二进制位
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ans = ans * 2 + u; //还原二进制数字为十进制
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}
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printf("%d", ans);
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return 0;
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} |