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python/TangDou/Dfs/DFS4_XuanShua_ByBox_2.cpp
HuangHai 1f397eca87 'commit'
2025-08-30 18:35:01 +08:00

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#include <bits/stdc++.h>
using namespace std;
const int N = 30;
const int INF = 0x3f3f3f3f;
int a[N];
bool st[N];
int n, k;
int cnt;
vector<int> path;
bool isPrime(int n) {
if (n < 2) return false;
for (int i = 2; i <= n / i; i++)
if (n % i == 0) return false;
return true;
}
/**
* 功能:遍历每个箱子,向箱子里装卡片
* @param step 走在第几个箱子面前
* @param sum 已经获得的数字和
* @return 获取可行方法数
*/
void dfs(int step, int sum) {
//当走到第k+1个虚拟箱子面前表示前面k个箱子已经装完
if (step == k + 1) {
if (isPrime(sum)) cnt++;
return;
}
//在没有走完箱子时,考虑当前箱子放哪张卡片
for (int i = path.size() == 0 ? 1 : path[path.size() - 1] + 1; i <= n; i++) {
if (!st[i]) {
st[i] = true;
path.push_back(i);
dfs(step + 1, sum + a[i]);
path.pop_back();
st[i] = false;
}
}
}
/*
4 3
3 7 12 19
答案1
*/
int main() {
cin >> n >> k;
for (int i = 1; i <= n; i++) cin >> a[i];
dfs(1, 0);
cout << cnt << endl;
return 0;
}