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python/TangDou/KaoShi/摘苹果[洪水覆盖].cpp
HuangHai 1f397eca87 'commit'
2025-08-30 18:35:01 +08:00

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/*
果园里有两种水果苹果1和梨子2起点6也是苹果。
从起点开始,不能碰到梨子,求最多能摘到多少个苹果。
输入:
3 4
2 1 2 1
1 6 1 2
1 1 1 2
输出:
7
*/
#include <bits/stdc++.h>
using namespace std;
const int N = 110;
typedef pair<int, int> PII;
int a[N][N];
int n, m;
int x, y;
int dx[] = {-1, 0, 1, 0}; //上右下左
int dy[] = {0, 1, 0, -1}; //上右下左
int bfs(int x, int y) {
queue<PII> q;
int cnt = 1;
q.push({x, y});
a[x][y] = 2;
while (q.size()) {
auto t = q.front();
q.pop();
for (int i = 0; i < 4; i++) {
int tx = t.first + dx[i], ty = t.second + dy[i];
if (tx == 0 || tx > n || ty == 0 || ty > m) continue;
if (a[tx][ty] == 1) {
q.push({tx, ty});
a[tx][ty] = 2;
cnt++;
}
}
}
return cnt;
}
int main() {
cin >> n >> m;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= m; j++) {
cin >> a[i][j];
if (a[i][j] == 6) x = i, y = j;
}
cout << bfs(x, y) << endl;
return 0;
}