44 lines
1.2 KiB
C++
44 lines
1.2 KiB
C++
#include <bits/stdc++.h>
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using namespace std;
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const int N = 260;
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struct node {
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int value;
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int winner;
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} nodes[N];
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//本题n的概念很奇葩，不是n个国家，是2^n个国家~,比如n=3,就是2^3个国家，即8个国家。
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int n;
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//函数定义：计算x结点的获胜者
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void dfs(int x) {
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//叶子结点
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if (x >= (1 << n)) return;
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//左子树，右子树
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dfs(2 * x), dfs(2 * x + 1);
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//左结点值，右结点值
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int lvalue = nodes[2 * x].value, rvalue = nodes[2 * x + 1].value;
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//pk
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if (lvalue > rvalue) nodes[x].value = lvalue, nodes[x].winner = nodes[2 * x].winner;
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else nodes[x].value = rvalue, nodes[x].winner = nodes[2 * x + 1].winner;
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}
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/**
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测试用例：
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3
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4 2 3 1 10 5 9 7
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*/
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int main() {
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cin >> n;
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for (int i = 0; i < (1 << n); i++) {//完美二叉树结点个数 2^n-1
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int k = i + (1 << n);
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cin >> nodes[k].value; //读入各个结点的能力值
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nodes[k].winner = i + 1; //叶子结点的获胜方就是自己国家的编号
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}
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dfs(1);//从根结点开始遍历
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//找亚军
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cout << ((nodes[2].value > nodes[3].value) ? nodes[3].winner : nodes[2].winner) << endl;
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return 0;
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} |