80 lines
2.0 KiB
C++
80 lines
2.0 KiB
C++
//#include <bits/stdc++.h>
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#include <iostream>
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#include <string.h>
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#include <stdio.h>
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#include <vector>
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#include <map>
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#include <queue>
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#include <algorithm>
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#include <math.h>
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#include <cstdio>
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using namespace std;
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typedef long long LL;
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const int N = 1e6 + 5;
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LL a[N];
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struct Node {
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int l, r;
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LL sum; //区间和
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} tr[N << 2];
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void pushup(int u) {
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tr[u].sum = tr[u << 1].sum + tr[u << 1 | 1].sum;
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}
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void build(int u, int l, int r) {
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tr[u] = {l, r};
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if (l == r) {
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tr[u].sum = a[l]; //构建线段树，叶子节点给定初始值
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return;
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}
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int mid = (l + r) >> 1;
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build(u << 1, l, mid), build(u << 1 | 1, mid + 1, r);
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//更新父节点信息
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pushup(u);
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}
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void modify(int u, int l, int r) {
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//减枝 如果区间和等于区间长度，说明每个节点值都是1，此时再开方没有意义
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if (tr[u].sum == (tr[u].r - tr[u].l + 1)) return;
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//如果在区间内
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if (tr[u].l == tr[u].r) {
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tr[u].sum = (LL)sqrt(tr[u].sum); //暴力开方
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return;
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}
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//中点
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int mid = (tr[u].l + tr[u].r) >> 1;
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//与左儿子有交集,递归修改左儿子
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if (l <= mid) modify(u << 1, l, r);
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//与右儿子有交集，递归修改右儿子
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if (r > mid) modify(u << 1 | 1, l, r);
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//向父节点传递统计信息
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pushup(u);
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}
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//非常标准的查询
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LL query(int u, int l, int r) {
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if (r < tr[u].l || l > tr[u].r) return 0;
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if (l <= tr[u].l && tr[u].r <= r) return tr[u].sum;
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return query(u << 1, l, r) + query(u << 1 | 1, l, r);
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}
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int main() {
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int n, q, cas = 1;
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scanf("%d", &n);
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for (int i = 1; i <= n; i++) scanf("%lld", &a[i]);
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build(1, 1, n);
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scanf("%d", &q);
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while (q--) {
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int c, l, r;
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scanf("%d%d%d", &c, &l, &r);
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if (l > r) swap(l, r); /// l可能大于r
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if (c == 0)
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modify(1, l, r);
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else
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printf("%lld\n", query(1, l, r));
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}
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printf("\n");
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return 0;
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} |