12 lines
308 B
C++
12 lines
308 B
C++
#include <bits/stdc++.h>
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using namespace std;
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int main() {
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//通用mod运算,重复输出指定的1-N的方法,注意(i-1)%20-1的妙处!
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for (int i = 1; i < 101; ++i) {
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cout << setw(4) << (i - 1) % 20 + 1 << " ";
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if (i % 20 == 0)cout << endl;
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}
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return 0;
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} |