24 lines
465 B
C++
24 lines
465 B
C++
#include <bits/stdc++.h>
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using namespace std;
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const int N = 1010;
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int f[N];
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int n;
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int main() {
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//输入
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cin >> n;
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//边界条件：1
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f[1] = 1;
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for (int i = 2; i <= n; i++) {
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//任何数字，独立成为一个
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f[i] = 1;
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//所有从1到它的一半的，都可以增加进来
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for (int j = 1; j <= i / 2; j++) f[i] += f[j];
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}
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//总个数
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cout << f[n] << endl;
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return 0;
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} |