24 lines
534 B
C++
24 lines
534 B
C++
#include <bits/stdc++.h>
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using namespace std;
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typedef long long LL;
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const int N = 3000010;
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//递推打表求逆元
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LL inv[N];
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void getInv(LL n, LL p) {
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inv[1] = 1;
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for (int i = 2; i <= n; i++)
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inv[i] = inv[p % i] * (p - p / i) % p;
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}
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int main() {
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LL n, p;
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cin >> n >> p;
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getInv(n, p);
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for (int i = 1; i <= n; i++) printf("%d\n", inv[i]); //可以AC
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// cout << inv[i] << "\n"; //可以AC
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// cout << inv[i] << endl; //这里使用cout就会TLE两个点!
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return 0;
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}
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