50 lines
1.3 KiB
C++
50 lines
1.3 KiB
C++
#include <bits/stdc++.h>
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using namespace std;
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// Rotate Image（二维数组逆时针旋转90度）
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const int N = 110;
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int n = 9, cnt;
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int res[N][N], f[N][N];
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//矩阵旋转，需要额外开创建一个临时的二维数组(防止出现交换赋值时，出现覆盖的问题)
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void rotate(int x, int y, int r) { // x:第几行 y:以(x,y)点为中心，四个方向，向左r,向右r，转~
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for (int i = -r; i <= r; i++)
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for (int j = -r; j <= r; j++) //
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f[x - j][y + i] = res[x + i][y + j]; //副本修改
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// 复制数组的正规写法
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memcpy(res, f, sizeof f); //将副本复制回到正本上
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//复制
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// for (int i = 1; i <= n; i++)
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// for (int j = 1; j <= n; j++)
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// res[i][j] = f[i][j];
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}
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int main() {
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//初始化填充数据
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for (int i = 1; i <= n; i++)
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for (int j = 1; j <= n; j++)
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res[i][j] = f[i][j] = ++cnt;
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//输出结果
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= n; j++)
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printf("%02d ", res[i][j]);
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printf("\n");
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}
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printf("\n");
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//测试一下旋转
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rotate(6, 7, 1);
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//输出结果
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for (int i = 1; i <= n; i++) {
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for (int j = 1; j <= n; j++)
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printf("%02d ", res[i][j]);
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printf("\n");
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}
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return 0;
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} |