78 lines
1.8 KiB
C++
78 lines
1.8 KiB
C++
#include <cstdio>
|
||
#include <cstring>
|
||
#include <algorithm>
|
||
#include <iostream>
|
||
|
||
using namespace std;
|
||
const int N = 1000010;
|
||
|
||
int n; // n个模式串
|
||
char s[N]; //模式串
|
||
char T[N]; //文本串
|
||
|
||
// Trie树
|
||
int tr[N][26], idx;
|
||
int cnt[N];
|
||
void insert(char *s, int x) {
|
||
int p = 0;
|
||
for (int i = 0; s[i]; i++) {
|
||
int t = s[i] - 'a';
|
||
if (!tr[p][t]) tr[p][t] = ++idx;
|
||
p = tr[p][t];
|
||
}
|
||
cnt[p]++; //以p为结束节点的字符串个数+1,如果有重复的,这里++也是OK的~
|
||
}
|
||
|
||
// AC自动机
|
||
int q[N], ne[N];
|
||
void bfs() {
|
||
int hh = 0, tt = -1;
|
||
for (int i = 0; i < 26; i++)
|
||
if (tr[0][i]) q[++tt] = tr[0][i];
|
||
|
||
while (hh <= tt) {
|
||
int p = q[hh++];
|
||
for (int i = 0; i < 26; i++) {
|
||
int t = tr[p][i]; //此处直接优化为Trie图,没有采用原始的while向上递归处理的办法,记忆这个版本即可
|
||
if (!t)
|
||
tr[p][i] = tr[ne[p]][i];
|
||
else {
|
||
ne[t] = tr[ne[p]][i];
|
||
q[++tt] = t;
|
||
}
|
||
}
|
||
}
|
||
}
|
||
|
||
//查询字符串s中 n个模式串出现了几个
|
||
int query(char *s) {
|
||
int p = 0;
|
||
int res = 0;
|
||
for (int i = 0; s[i]; i++) {
|
||
p = tr[p][s[i] - 'a'];
|
||
for (int j = p; j; j = ne[j]) {
|
||
if (cnt[j] == -1) break;
|
||
res += cnt[j];
|
||
cnt[j] = -1;
|
||
}
|
||
}
|
||
return res;
|
||
}
|
||
|
||
int main() {
|
||
//加快读入
|
||
ios::sync_with_stdio(false), cin.tie(0);
|
||
cin >> n;
|
||
//构建Trie树
|
||
for (int i = 1; i <= n; i++) {
|
||
cin >> s;
|
||
insert(s, i);
|
||
}
|
||
//构建AC自动机
|
||
bfs();
|
||
//输入文本串
|
||
cin >> T;
|
||
//输出模式串出现的个数(注意:不是次数,是个数)
|
||
printf("%d\n", query(T));
|
||
return 0;
|
||
} |