66 lines
1.9 KiB
C++
66 lines
1.9 KiB
C++
#include <bits/stdc++.h>
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using namespace std;
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const int N = 5e5 + 10, M = 4e6 + 10;
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int e[M], h[N], idx, w[M], ne[M];
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void add(int a, int b, int c = 0) {
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e[idx] = b, ne[idx] = h[a], w[idx] = c, h[a] = idx++;
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}
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int dfn[N], low[N], stk[N], top, ts, root;
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int n, m;
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// 边双模板
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int bcnt;
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vector<int> bcc[N];
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// 这里与有向图的强连通分量有区别，那个是id[N]+sz[N]静态数组实现，记录的是某个点在哪个强连通分量中，
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// 而这里，记录的是某个边双连通分量中有哪些节点，是捋着的顺序不同，实现方式不同，无法追求统一，否则就会在某种场景下造成使用双重循环使得代码TLE掉，
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// 不要问我是怎么知道的~
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void tarjan(int u, int from) {
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dfn[u] = low[u] = ++ts;
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stk[++top] = u;
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// 边双连通分量模板，对比有向图强连通分量，只用栈记录数据，并没有用状态数组in_stk标识是否某节点在栈中
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for (int i = h[u]; ~i; i = ne[i]) {
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int v = e[i];
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if (!dfn[v]) {
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tarjan(v, i); // v:点，i:哪条边
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low[u] = min(low[u], low[v]);
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} else if (i != (from ^ 1))
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low[u] = min(low[u], dfn[v]);
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}
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if (dfn[u] == low[u]) {
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++bcnt; // 边双数量+1
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int x;
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do {
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x = stk[top--];
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bcc[bcnt].push_back(x); // 记录边双中有哪些点
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} while (x != u);
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}
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}
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int main() {
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memset(h, -1, sizeof h);
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scanf("%d %d", &n, &m);
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while (m--) {
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int a, b;
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scanf("%d %d", &a, &b);
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if (a != b) add(a, b), add(b, a);
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}
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for (root = 1; root <= n; root++)
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if (!dfn[root]) tarjan(root, -1);
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// 个数
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printf("%d\n", bcnt);
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for (int i = 1; i <= bcnt; i++) {
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printf("%d ", bcc[i].size());
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for (auto j : bcc[i]) printf("%d ", j);
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printf("\n");
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}
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return 0;
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} |