50 lines
1.7 KiB
C++
50 lines
1.7 KiB
C++
#include <bits/stdc++.h>
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using namespace std;
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//https://zhuanlan.zhihu.com/p/265677795
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char encoder[26] = {'C', 'S', 'P'};//声明26个长度的字符数组，只初始化了前三个，后面23个默认是0，即 \000
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char decoder[26]; //声明一个字符数组，没有进行初始化，默认值是0,即 \000
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string st;
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int main() {
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int k = 0;
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for (int i = 0; i < 26; i++)
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if (encoder[i] != 0) ++k; //因为有三个进行了初始化，所以k=3
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for (char x = 'A'; x <= 'Z'; ++x) { //x的意思是遍历每一个大写字母
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bool flag = true;
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for (int i = 0; i < 26; ++i)
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if (encoder[i] == x) {
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flag = false; //如果在 encoder数组中找到，则 flag=false,并且停止循环
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break;
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}
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if (flag) { //如果没有找到,那么依次填充到encoder数组中
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encoder[k] = x;
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++k;
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}
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}
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//根据encoder换算出decoder
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for (int i = 0; i < 26; ++i) {
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decoder[encoder[i] - 'A'] = i + 'A'; //这句加密算法是核心
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}
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//这里应该输出一下decoder,就清楚了,如果是笔试，那么需要用笔把26个都描述出来
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for (int i = 0; i < 26; ++i) {
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cout << "encoder[" << i << "]=" << encoder[i] << " " << endl;
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}
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for (int i = 0; i < 26; ++i) {
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cout << "decoder[" << i << "]=" << decoder[i] << " " << endl;
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}
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for (int i = 0; i < 26; i++) {
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cout << char('A' + i) << ":" << i << " ";
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}
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cout << endl;
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//输入一个字符串，遍历每一个字符，进行解码
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cin >> st;
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for (int i = 0; i < (int)st.length(); ++i)
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st[i] = decoder[st[i] - 'A'];
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cout << st;
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return 0;
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}
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