82 lines
1.9 KiB
C++
82 lines
1.9 KiB
C++
#include <bits/stdc++.h>
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using namespace std;
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//函数：r进制转换成10进制
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int rToTen(string n, int r) {
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//将r进制转为10进制，n是该r进制的字符串表示
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int len = n.length();
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int ans = 0;
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int i = 0;
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while (i < len) {
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ans *= r;
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if (n[i] >= '0' && n[i] <= '9') ans += n[i] - '0';
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if (n[i] >= 'A' && n[i] <= 'Z') ans += n[i] - 'A' + 10;
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if (n[i] >= 'a' && n[i] <= 'z') ans += n[i] - 'a' + 10 + 26;
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i++;
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}
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return ans;
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}
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//函数：十进制转任意进制
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string tenToR(int n, int r) {
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if (n == 0) return "0";
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//十进制n转r进制 ，返回字符串s
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string str = "";
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stack<int> s;
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while (n) {
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s.push(n % r);
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n = n / r;
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}
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while (!s.empty()) {
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switch (s.top()) {
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case 10:
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str += 'A';
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break;
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case 11:
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str += 'B';
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break;
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case 12:
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str += 'C';
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break;
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case 13:
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str += 'D';
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break;
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case 14:
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str += 'E';
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break;
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case 15:
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str += 'F';
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break;
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default:
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str += s.top() + '0';
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}
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s.pop();
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}
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return str;
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}
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int main() {
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int n;
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cin >> n;
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long long min = INT32_MAX;
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long long a[100] = {0};
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for (int i = 0; i < n; ++i) {
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string pai;
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cin >> pai;
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pai = pai.substr(2, pai.length() - 2);//裁掉SD
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//pai按36进制转为10进制
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a[i] = rToTen(pai, 36);
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}
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//排序,由大到小
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sort(a, a + 100, less<long long>());
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// 计算差值
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for (int i = 99; i > 99 - n; i--) {
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if (a[i] - a[i - 1] < min)min = a[i] - a[i - 1];
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}
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cout << min << endl;
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return 0;
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}
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